The Obligatory RSA Challenge

RSA with factorable n

Problem

Would you believe last year someone complained because we didn't have any RSA challenges?

Solution

Passing n into factordb, we see that n is a square.

Decoding is then trivial. Note that since n=p2n=p^2, ϕ(n)=p(p1)\phi(n)=p(p-1) instead of (p1)2(p-1)^2.

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